| 摘要 |
PROBLEM TO BE SOLVED: To make it possible to supply a load with a peak power that exceeds the average power supply capacity of a power supply without increasing the average power supply capacity of the power supply. SOLUTION: A power supply 10 has a large capacity capacitor 15, a charging means 11, 12 for this capacitor 15, a DC power supply 1 and a diode 13. When the output voltage value of this power supply 1 becomes lower than the terminal voltage of the capacitor 15, the diode 13 is turned on so as to enable electric power to be supplied from the capacitor 15 to a load 4 through the diode 13. Thus, by cutting the peak power that is supplied from the power supply 10 to the load 4, the peak power is supplied for the load 4 without increasing the average power supply capacity of the power supply 10.
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