| 摘要 |
PROBLEM TO BE SOLVED: To preferentially repeat a response packet corresponding to a request packet received later.SOLUTION: A time interval t between a timing when a request packet is received and a current time is calculated, and the time interval t is divided by a predetermined time length T for obtaining a value [t/T] (S43). The value [t/T] is subtracted from an initial value (P in the drawings) of priority of a response packet (S45). When a value p is larger than 0 (S47: YES), the priority 106 is substituted by the priority 106 equal to the value p (S49). |
