摘要 |
PROBLEM TO BE SOLVED: To protect a specific protection target from radiation by shielding the radiation.SOLUTION: A radiation protector comprises a radiation absorber 2 which absorbs radiation. When a thickness of the radiation absorber 2 is defined as (x), an attenuation coefficient for γ rays is defined as μ, a proportional constant (atomic attenuation coefficient) is defined as &egr;, a mass volume density is defined as &rgr;, a radiation intensity before transmission through a radiation shield container is defined as Iand a radiation intensity after transmission through the radiation shield container is defined as I, the radiation absorber 2 has the thickness calculated by the formula (1). |