| 摘要 |
Opposite ends (11, 35) of strut (10) engage opposed shoes of a drum brake. During braking, strut (10) is free to lengthen to compensate for brake lining wear. Leaf spring (24) pressing against neck (29) of nut (27) tends to extend strut (10), however this extension is opposed by the engagement of foot (40) of arm (37) with axially disposed face (32) of nut (27). Due to a resilient pivoting action of, and oblique positioning of, arm (37) with respect to cam teeth (31) on face (32) such extension forces are converted into turning of nut (27), leading to axial extension of screw (33) and thus extension of strut (10). Reverse rotation of nut (27) upon release of braking is opposed by frictional contact between it and leaf spring (24).
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