| 摘要 |
PROBLEM TO BE SOLVED: To perform block interleave, using memory capacity for one interleave. SOLUTION: This interleaver performs block interleave for a unit of m×n data. The interleaver sets logical addresses from 0 to (m×n-1) to an interleave memory and writes i-th data of the next super frame to the logical address, where i-th data of a certain interleave block are read out. The interleaver calculates the logical address of i-th data to be outputted from a k-th interleave block, on the basis of a function fk(i)=f(fk-1(i)).
|
