摘要 |
<p>PROBLEM TO BE SOLVED: To always know the position of a cursor by changing the displaying timing of lighting display and reverse display when the position of the cursor is changed, so as to change to reverse display even when the display timing is lighting display. SOLUTION: Whether display change occurs is judged (2-1) and when it does not occur, the judgement (2-1) of display change is repeated again. On the other hand, when display change occurs, whether the positional change of the cursor occurs or not is judged (2-2) and when it occurs, a request for optionally changing the display timing is set (2-3) to change to reverse display (2-4). Then, when the positional change of the cursor does not occur, whether the display timing is reverse display is judged (2-5) to execute lighting display at the time of not being reverse display but to continue reverse display (2-4) at the time of reverse display.</p> |